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8.33x^2-2.24x=0
a = 8.33; b = -2.24; c = 0;
Δ = b2-4ac
Δ = -2.242-4·8.33·0
Δ = 5.0176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.24)-\sqrt{5.0176}}{2*8.33}=\frac{2.24-\sqrt{5.0176}}{16.66} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.24)+\sqrt{5.0176}}{2*8.33}=\frac{2.24+\sqrt{5.0176}}{16.66} $
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